Wednesday, September 30, 2015

pnp transistor

The PNP Transistor

The PNP Transistor is the exact opposite to the NPN Transistor device we looked at in the previous tutorial. Basically, in this type of transistor construction the two diodes are reversed with respect to the NPN type giving a Positive-Negative-Positive type of configuration, with the arrow which also defines the Emitter terminal this time pointing inwards in the transistor symbol.
Also, all the polarities for a PNP transistor are reversed which means that it “sinks” current into its Base as opposed to the NPN Transistor which “sources” current through its Base. The main difference between the two types of transistors is that holes are the more important carriers for PNP transistors, whereas electrons are the important carriers for NPN transistors.
Then, PNP transistors use a small base current and a negative base voltage to control a much larger emitter-collector current. In other words for a PNP transistor, the Emitter is more positive with respect to the Base and also with respect to the Collector.
The construction of a “PNP transistor” consists of two P-type semiconductor materials either side of an N-type material as shown below.

A PNP Transistor Configuration

pnp transistor
(Note: Arrow defines the emitter and conventional current flow, “in” for a PNP transistor.)
 
The construction and terminal voltages for an NPN transistor are shown above. The PNP Transistor has very similar characteristics to their NPN bipolar cousins, except that the polarities (or biasing) of the current and voltage directions are reversed for any one of the possible three configurations looked at in the first tutorial, Common Base, Common Emitter and Common Collector.
bipolar pnp transistor
PNP Transistor Connection
The voltage between the Base and Emitter ( VBE ), is now negative at the Base and positive at the Emitter because for a PNP transistor, the Base terminal is always biased negative with respect to the Emitter.
Also the Emitter supply voltage is positive with respect to the Collector ( VCE ). So for a PNP transistor to conduct the Emitter is always more positive with respect to both the Base and the Collector.
The voltage sources are connected to a PNP transistor are as shown. This time the Emitter is connected to the supply voltage VCC with the load resistor, RL which limits the maximum current flowing through the device connected to the Collector terminal. The Base voltage VB which is biased negative with respect to the Emitter and is connected to the Base resistor RB, which again is used to limit the maximum Base current.
To cause the Base current to flow in a PNP transistor the Base needs to be more negative than the Emitter (current must leave the base) by approx 0.7 volts for a silicon device or 0.3 volts for a germanium device with the formulas used to calculate the Base resistor, Base current or Collector current are the same as those used for an equivalent NPN transistor and is given as.
pnp transistor base current
 
We can see that the fundamental differences between a NPN Transistor and a PNP Transistor is the proper biasing of the transistors junctions as the current directions and voltage polarities are always opposite to each other. So for the circuit above: Ic = Ie – Ib as current must leave the Base.
Generally, the PNP transistor can replace NPN transistors in most electronic circuits, the only difference is the polarities of the voltages, and the directions of the current flow. PNP transistors can also be used as switching devices and an example of a PNP transistor switch is shown below.

A PNP Transistor Circuit

pnp transistor as a switch
 
The Output Characteristics Curves for a PNP transistor look very similar to those for an equivalent NPN transistor except that they are rotated by 180o to take account of the reverse polarity voltages and currents, (the currents flowing out of the Base and Collector in a PNP transistor are negative). The same dynamic load line can be drawn onto the I-V curves to find the PNP transistors operating points.

Transistor Matching

complementary transistors
Complementary Transistors
You may think what is the point of having a PNP Transistor, when there are plenty of NPN Transistors available that can be used as an amplifier or solid-state switch?. Well, having two different types of transistors “PNP” and “NPN”, can be a great advantage when designing power amplifier circuits such as the Class B Amplifier.
Class-B amplifiers uses “Complementary” or “Matched Pair” (that is one PNP and one NPN connected together) transistors in its output stage or in reversible H-Bridge motor control circuits were we want to control the flow of current evenly through the motor in both directions.
A pair of corresponding NPN and PNP transistors with near identical characteristics to each other are calledComplementary Transistors for example, a TIP3055 (NPN transistor) and the TIP2955 (PNP transistor) are good examples of complementary or matched pair silicon power transistors. They both have a DC current gain, Beta, ( Ic/Ib ) matched to within 10% and high Collector current of about 15A making them ideal for general motor control or robotic applications.
Principles of Transistor Circuits, Ninth Edition
List Price$79.95
Current Price$41.65
Buy Now
Price Disclaimer
Also, class B amplifiers use complementary NPN and PNP in their power output stage design. The NPN transistor conducts for only the positive half of the signal while the PNP transistor conducts for negative half of the signal.
This allows the amplifier to drive the required power through the load loudspeaker in both directions at the stated nominal impedance and power resulting in an output current which is likely to be in the order of several amps shared evenly between the two complementary transistors.

Identifying the PNP Transistor

We saw in the first tutorial of this transistors section, that transistors are basically made up of two Diodes connected together back-to-back.
We can use this analogy to determine whether a transistor is of the PNP type or NPN type by testing its Resistance between the three different leads, EmitterBase andCollector. By testing each pair of transistor leads in both directions with a multimeter will result in six tests in total with the expected resistance values in Ohm’s given below.
  • 1. Emitter-Base Terminals – The Emitter to Base should act like a normal diode and conduct one way only.
  • 2. Collector-Base Terminals – The Collector-Base junction should act like a normal diode and conduct one way only.
  • 3. Emitter-Collector Terminals – The Emitter-Collector should not conduct in either direction.

Transistor Resistance Values for a PNP Transistor and a NPN Transistor

Between Transistor TerminalsPNPNPN
CollectorEmitterRHIGHRHIGH
CollectorBaseRLOWRHIGH
EmitterCollectorRHIGHRHIGH
EmitterBaseRLOWRHIGH
BaseCollectorRHIGHRLOW
BaseEmitterRHIGHRLOW
 
Then we can define a PNP Transistor as being normally “OFF” but a small output current and negative voltage at its Base ( B ) relative to its Emitter ( E ) will turn it “ON” allowing a much large Emitter-Collector current to flow. PNP transistors conduct when Ve is much greater than Vc.
In other words, a Bipolar PNP Transistor will ONLY conduct if both the Base and Collector terminals are negative with respect to the Emitter
In the next tutorial about Bipolar Transistors instead of using the transistor as an amplifying device, we will look at the operation of the transistor in its saturation and cut-off regions when used as a solid-state switch. Bipolar transistor switches are used in many applications to switch a DC current “ON” or “OFF”, from LED’s which require only a few milliamps of switching current at low DC voltages, or motors and relays which may require higher currents at higher voltages.

Monday, September 28, 2015

current divider rule

current divider rule

In electronics, a current divider is a simple linear circuit that produces an output current (IX) that is a fraction of its input current (IT). Current division refers to the splitting of current between the branches of the divider. The currents in the various branches of such a circuit will always divide in such a way as to minimize the total energy expended.

The formula describing a current divider is similar in form to that for the voltage divider. However, the ratio describing current division places the impedance of the considered branches in the denominator, unlike voltage division where the considered impedance is in the numerator. This is because in current dividers, total energy expended is minimized, resulting in currents that go through paths of least impedance, therefore the inverse relationship with impedance. On the other hand, voltage divider is used to satisfy Kirchhoff's Voltage Law. The voltage around a loop must sum up to zero, so the voltage drops must be divided evenly in a direct relationship with the impedance.

To be specific, if two or more impedances are in parallel, the current that enters the combination will be split between them in inverse proportion to their impedances (according to Ohm's law). It also follows that if the impedances have the same value the current is split equally.


Current divider:
A general formula for the current IX in a resistor RX that is in parallel with a combination of other resistors of total resistance RT is (see Figure 1):

I_X = \frac{R_T}{(R_X)+(R_T)}I_T \ 
where IT is the total current entering the combined network of RX in parallel with RT. Notice that when RT is composed of a parallel combination of resistors, say R1, R2, ... etc., then the reciprocal of each resistor must be added to find the total resistance RT:

 \frac {1}{R_T} = \frac {1} {R_1} + \frac {1} {R_2} + \frac {1}{R_3} + ... \ . 
General case[edit]
Although the resistive divider is most common, the current divider may be made of frequency dependent impedances. In the general case the current IX is given by:

I_X = \frac{Z_T} {Z_X+Z_T}I_T \ ,[1]
Using Admittance[edit]
Instead of using impedances, the current divider rule can be applied just like the voltage divider rule if admittance (the inverse of impedance) is used.

I_X = \frac{Y_X} {Y_{Total}}I_T
Take care to note that YTotal is a straightforward addition, not the sum of the inverses inverted (as you would do for a standard parallel resistive network). For Figure 1, the current IX would be

I_X = \frac{Y_X} {Y_{Total}}I_T = \frac{\frac{1}{R_X}} {\frac{1}{R_X} + \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}}I_T

Sunday, September 27, 2015

physics all equation

Mechanics
 = 
Δs
Δt
v = 
ds
dt

 = 
Δv
Δt
a = 
dv
dt

v = v0 + at
x
 = x0 + v0t + ½at2
v2
 = v02 + 2a(x − x0)
 = ½(v + v0)

∑ F = m a
∑ F = 
dp
dt

W = m g

ƒ = μN

ac = 
v2
r
ac = − ω2 r

p = m v

J =  Δt
J = 

F dt

 Δt = m Δv

F dt = Δp

W = Δs cos θ
W = 

F · ds

Δs cos θ = ΔE

F · ds = ΔE

K = ½mv2

ΔU = − 

F · ds
F = − U

ΔUg = mgΔh

 
Wout
Ein

 = 
ΔW
Δt
 = F̅v cos θ
P = 
dW
dt
P = F · v

ω̅ = 
Δθ
Δt
ω = 
dθ
dt
v = ω × r

α̅ = 
Δω
Δt
α = 
dω
dt
a = α × r − ω2 r

ω = ω0 + αt
θ = θ0 + ω0t + ½αt2
ω2 = ω02 + 2α(θ − θ0)
ω̅ = ½(ω + ω0)

∑ τ = I α
∑ τ = 
dL
dt

τ = rF sin θ
τ = r × F

I = ∑ mr2
I = 

 r2 dm

W = τ̅Δθ
W = 

 τ · dθ

P = τω cos θ
P = τ · ω

K = ½Iω2

L = mrv sin θ
L
 = r × p
L
 = I ω

Fg = − 
Gm1m2
 
r2

g = − 
Gm
 
r2

Ug = − 
Gm1m2
r

Vg = − 
Gm
r

v = √ 
Gm
r

v = √ 
2Gm
r

F = − k Δx

Us = ½kΔx2

T = 2π √ 
m
k

T = 2π √ 
g

ƒ = 
1
T

ω = 2πƒ

ρ = 
m
V

P = 
F
A

P = P0 + ρgh

B = ρgVdisplaced

I = 
m
t

φ = 
V
t

ρ1A1v1 = ρ2A2v2

A1v1 = A2v2

P1 + ρgy1 + ½ρv12 =
 P2 + ρgy2 + ½ρv22

η = 
/A
Δvxz
η = 
F/A
dvx/dz

ν = 
η
ρ

R = ½ρCAv2

Ma = 
v
c

Re = 
ρvD
η

Fr = 
v
g

F
 = E 
Δℓ
A
0

F
 = G 
Δx
A
y

F
 = K 
ΔV
A
V0

γ = 
F
Thermal Physics
Δℓ = αℓ0ΔT
ΔA = 2αA0ΔT
ΔV = 3αV0ΔT

ΔV = βV0ΔT

Q = mcΔT

Q = mL

PV = nRT

molecular constants
nR =Nk

− 
mv2
p(v) = 
4v2

m
3/2
e
2kT
√π
2kT

K 
3
 kT
2

vp = √ 
2kT
m
v = √8kTπm
vrms = √ 
3kT
m

Φ̅ = 
ΔQ
Δt
Φ = 
dQ
dt

Φ = 
kAΔT

Φ = εσA(T4 − T04)

λmax = 
b
T

ΔU = 32nRΔT

W = −

P dV

ΔU = Q + W

ΔS = 
ΔQ
T
S = k log w

real = 1 − 
QC
QH
ideal = 1 − 
TC
TH

COPreal = 
QC
QH − QC
COPideal = 
TC
TH − TC
Waves & Optics
v = ƒλ

ƒ = 
1
T

fbeat = fhigh − flow

I = 
P
A

LI = 10 log

I

I0

LP = 20 log

Pmax

P0

nλ = d sin θ
nλ
 ≈ 
x
d
L

n = 
c
v

n1 sin θ1 = n2 sin θ2

sin θc = 
n2
n1

1
 = 
1
 + 
1
ƒ
do
di

M = 
hi
 = 
di
ho
do

ƒ ≈ 
r
2
Electricity & Magnetism
F = k 
q1q2
r2

E = 
FE
q

E = k ∑ 
q
 
r2
E = k 

dq
 
r2

 = − 
V
d
E = − V

ΔV = 
ΔUE
q

V = k ∑ 
q
r
V = k 

dq
r

C = 
Q
V

C = 
κε0A
d

C = 
2πκε0
ln (b/a)

C = 
4πκε0
(1/a) − (1/b)

U = 
1
 CV2 = 
1

Q2
 = 
1
 QV
2
2
C
2

 = 
Δq
Δt
I = 
dq
dt

V = IR
E
 = ρ J
J
 = σE

ρ = 
1
σ

R = 
ρℓ
A

P = VI = I2R = 
V2
R

Rs = ∑ Ri

1
 = ∑ 
1
Rp
Ri

1
 = ∑ 
1
Cs
Ci

Cp = ∑ Ci

FB = qvB sin θ
FB = q v × B

FB = IB sin θ
dFB = I d × B

B = 
μ0I

ds × 
r2

B = µ0nI

B = 
μ0I
r

FB
 = 
μ0

I1I2
r

ΦE = EA cos θ
ΦE = 

E · dA

ΦB = BA cos θ
ΦB = 

B · dA

 Bv

̅ = − 
ΔΦB
Δt
 = − 
dΦB
dt

 E · dA = 
Q
ε0
 · E = 
ρ
ε0

no one's law
 B · dA =

0

 · B =

0


E · ds = − 
dΦB
dt
 × E = − 
B
t

B · ds = μ0ε0 
dΦE
 + μ0I
dt
 × B = μ0ε0 
E
 + μ0 J
t
Modern Physics
t' = 
t
√(1 − v2/c2)

ℓ' = ℓ √(1 − v2/c2)

m' = 
m
√(1 − v2/c2)

u' = 
u + v
1 + uv/c2

E = 
mc2
√(1 − v2/c2)

p = 
mv
√(1 − v2/c2)

E2 = p2c2 + m02c4

E = mc2

λ
 = 
ƒ0
 = √ 

1 + v/c

λ0
ƒ
1 − v/c

E = hf

Kmax = E − ϕ h(ƒ − ƒ0)

p = 
h
λ

i 
 Ψ(r,t) = − 
2
 2Ψ(r,t) + V(r)Ψ(r,t)
∂t
2m
Eψ(r) = − 
2
 2ψ(r) + V(r)ψ(r)
2m

Δpx Δx ≥ 
 
2
ΔE Δt ≥ 
 
2

1
 = −R 

1
 − 
1

λ
n2
n02

N = N02t